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Write a balanced chemical equation for the overall reaction represented by the cell notation below.Mn(s) | Mn2+(aq) || Zn2+(aq) | Zn(s)


A) 2Mn(s) + Zn2+(aq) \to Zn(s) + 2Mn2+(aq)
B) Mn(s) + Mn2+(aq) \to Zn(s) + Zn2+(aq)
C) Mn(s) + Zn2+(aq) \to Zn(s) + Mn2+(aq)
D) 2Zn(s) + Mn2+(aq) \to Mn(s) + 2Zn2+(aq)
E) Zn(s) + Mn2+(aq) \to Mn(s) + Zn2+(aq)

F) B) and C)
G) A) and B)

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What is the standard cell potential (  What is the standard cell potential (   ) for the following below, 2Ag(s) + Pb<sup>2+</sup>(aq)  \to  2Ag<sup>+</sup>(aq) + Pb(s)  Given the following standard reduction potentials. Ag<sup>+</sup>(aq) + e<sup>-</sup> \to  Ag(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> =0.8 V Pb<sup>2+</sup>(aq) +2e<sup>-</sup> \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> =-0.126 V A)  -0.926 V B)  0.926 V C)  -1.726 V D)  1.726 V E)  1.474 V ) for the following below, 2Ag(s) + Pb2+(aq) \to 2Ag+(aq) + Pb(s) Given the following standard reduction potentials. Ag+(aq) + e- \to Ag(s)         ~~~~~~~~        ~~~~~~~~ E \circ =0.8 V Pb2+(aq) +2e- \to Pb(s)         ~~~~~~~~        ~~~~~~~~ E \circ =-0.126 V


A) -0.926 V
B) 0.926 V
C) -1.726 V
D) 1.726 V
E) 1.474 V

F) D) and E)
G) C) and E)

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Calculate E°cell for the cell for the reaction below, 2Cr(s) + 3Sn4+(aq) \to 3Sn2+(aq) +2Cr3+(aq) Given the following standard reduction potentials. Cr3+(aq) + 3e- \to Cr(s)         ~~~~~~~~        ~~~~~~~~ E \circ = -0.74 V Sn4+(aq) + 2e- \to Sn2+(aq)         ~~~~~~~~   ~ ~~ E \circ = 0.15V


A) 0.89 V
B) 0.59 V
C) 0.42 V
D) -0.59 V
E) (-0.89) V

F) C) and D)
G) A) and B)

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Al3+ is reduced to Al(s) at an electrode.If a current of 2.75 ampere is passed for 36 hours,what mass of aluminum is deposited at the electrode? Assume 100% current efficiency.


A) 9.2 ×\times 10-3 g
B) 3.3 ×\times 101 g
C) 9.9 ×\times 101 g
D) 1.0 ×\times 102 g
E) 3.0 ×\times 102 g

F) A) and B)
G) B) and D)

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Which of the following statements is/are CORRECT? 1) A nickel-cadmium battery is an example of a secondary or rechargeable battery,often used in rechargeable cordless appliances. 2) Hydrogen-oxygen fuel cells use the heat of combustion of hydrogen to recharge lead storage batteries. 3) LeClanché cells are the most efficient rechargeable batteries,but they are rarely used due their high cost of production.


A) 1 only
B) 2 only
C) 3 only
D) 1 and 3
E) 1,2,and 3

F) All of the above
G) C) and D)

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Write balanced reduction and oxidation half-reactions for the processes that occur at the cathode and anode of a fuel cell used aboard NASA's space shuttles.

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Cathode: O2(g)+ 2 H...

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For the cell reaction For the cell reaction   l )  The standard cell potential is 1.34 V.To determine the cell potential at nonstandard conditions,what is the value that should be used for n in the Nernst equation? A)  8 B)  10 C)  5 D)  2 E)  6 l ) The standard cell potential is 1.34 V.To determine the cell potential at nonstandard conditions,what is the value that should be used for n in the Nernst equation?


A) 8
B) 10
C) 5
D) 2
E) 6

F) A) and D)
G) A) and B)

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In the following electrochemical cell,what is the reduction half reaction? Cu(s) | Cu2+(aq) || Fe3+(aq) ,Fe2+(aq) | Pt(s)


A) Fe3-(aq) + e- \to Fe2(aq)
B) Fe2-(aq) + e- \to Fe3+(aq)
C) Fe2+(aq) + Pt(s) \to Fe3+0(aq) + e-
D) Cu2+(aq) \to Cu(s) + 2e-
E) Cu(s) \to Cu2+(aq) + 2e-

F) A) and B)
G) A) and C)

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A

Calculate Ecell for the following electrochemical cell at 25°C given that the standard cell potential, E°cell,is 0.460 V. Cu(s) | Cu2+(aq,0.012 M) || Ag+(aq,0.17 M) | Ag(s)


A) 0.471 V
B) 0.282 V
C) 0.460 V
D) 0.494 V
E) 0.486 V

F) All of the above
G) C) and E)

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An SHE electrode has been assigned a standard reduction potential,E \circ ,of 0.00 Volts.Which reaction occurs at this electrode?


A) 2 H2O(  An SHE electrode has been assigned a standard reduction potential,E<sup> \circ </sup>,of 0.00 Volts.Which reaction occurs at this electrode? A)  2 H<sub>2</sub>O(   ) + 2 e<sup>-</sup>  \to  H<sub>2</sub>(g) + 2 OH<sup>-</sup>(aq)  B)  O<sub>2</sub>(g) + 4 e<sup>-</sup>  \to 2 O<sup>2-</sup>(aq)  C)  Hg<sub>2</sub>Cl<sub>2</sub>(s) + 2 e<sup>-</sup>  \to  2 Hg(   ) + 2 Cl<sup>-</sup>(aq)  D)  Li<sup>+</sup>(aq) + e<sup>-</sup>  \to  Li(s)  E)  2 H<sup>+</sup>(aq) + 2 e<sup>-</sup>  \to  H<sub>2</sub>(g)  ) + 2 e- \to H2(g) + 2 OH-(aq)
B) O2(g) + 4 e- \to 2 O2-(aq)
C) Hg2Cl2(s) + 2 e- \to 2 Hg(  An SHE electrode has been assigned a standard reduction potential,E<sup> \circ </sup>,of 0.00 Volts.Which reaction occurs at this electrode? A)  2 H<sub>2</sub>O(   ) + 2 e<sup>-</sup>  \to  H<sub>2</sub>(g) + 2 OH<sup>-</sup>(aq)  B)  O<sub>2</sub>(g) + 4 e<sup>-</sup>  \to 2 O<sup>2-</sup>(aq)  C)  Hg<sub>2</sub>Cl<sub>2</sub>(s) + 2 e<sup>-</sup>  \to  2 Hg(   ) + 2 Cl<sup>-</sup>(aq)  D)  Li<sup>+</sup>(aq) + e<sup>-</sup>  \to  Li(s)  E)  2 H<sup>+</sup>(aq) + 2 e<sup>-</sup>  \to  H<sub>2</sub>(g)  ) + 2 Cl-(aq)
D) Li+(aq) + e- \to Li(s)
E) 2 H+(aq) + 2 e- \to H2(g)

F) C) and E)
G) All of the above

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Calculate  Calculate   for the electrochemical cell below, Ag(s) | AgCl(s) | Cl<sup>-</sup>(aq,1.0 M) || Cu<sup>2+</sup>(aq,1.0 M) | Cu(s)  Given the following standard reduction potentials.  Cu<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Cu(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup>= +0.337 V AgCl(s) + e<sup>-</sup>  \to Ag(s) + Cl<sup>-</sup>(aq)  ~~~~~~~~ E<sup> \circ </sup> = +0.222 V A)  -0.115 V B)  -0.107 V C)  +0.115 V D)  +0.452 V E)  +0.559 V for the electrochemical cell below, Ag(s) | AgCl(s) | Cl-(aq,1.0 M) || Cu2+(aq,1.0 M) | Cu(s) Given the following standard reduction potentials. Cu2+(aq) + 2 e- \to Cu(s)         ~~~~~~~~        ~~~~~~~~ E \circ = +0.337 V AgCl(s) + e- \to Ag(s) + Cl-(aq)         ~~~~~~~~ E \circ = +0.222 V


A) -0.115 V
B) -0.107 V
C) +0.115 V
D) +0.452 V
E) +0.559 V

F) C) and E)
G) A) and D)

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Explain the function of a salt bridge in a voltaic cell.

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The salt bridge physically connects the ...

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Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb2+(aq) + 2 e- \to Pb(s)         ~~~~~~~~        ~~~~~~~~ E \circ = -0.126 V Fe3+(aq) + e- \to Fe2+(s)         ~~~~~~~~        ~~~~~~~~ E \circ = +0.771 V


A) Pb2+(aq) + 2 Fe2+(s) \to Pb(s) + 2 Fe3+(aq)  Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = -0.126 V Fe<sup>3+</sup>(aq) + e<sup>-</sup>  \to  Fe<sup>2+</sup>(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = +0.771 V A)  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)  \to Pb(s) + 2 Fe<sup>3+</sup>(aq)    = +0.897 V B)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)  \to  Pb(s) + Fe<sup>3+</sup>(aq)    = +0.645 V C)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +1.416 V D)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +0.897 V E)  Pb(s) + Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)    = +0.645 V = +0.897 V
B) Pb2+(aq) + Fe2+(s) \to Pb(s) + Fe3+(aq)  Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = -0.126 V Fe<sup>3+</sup>(aq) + e<sup>-</sup>  \to  Fe<sup>2+</sup>(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = +0.771 V A)  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)  \to Pb(s) + 2 Fe<sup>3+</sup>(aq)    = +0.897 V B)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)  \to  Pb(s) + Fe<sup>3+</sup>(aq)    = +0.645 V C)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +1.416 V D)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +0.897 V E)  Pb(s) + Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)    = +0.645 V = +0.645 V
C) Pb(s) + 2 Fe3+(aq) \to Pb2+(aq) + 2 Fe2+(s)  Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = -0.126 V Fe<sup>3+</sup>(aq) + e<sup>-</sup>  \to  Fe<sup>2+</sup>(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = +0.771 V A)  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)  \to Pb(s) + 2 Fe<sup>3+</sup>(aq)    = +0.897 V B)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)  \to  Pb(s) + Fe<sup>3+</sup>(aq)    = +0.645 V C)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +1.416 V D)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +0.897 V E)  Pb(s) + Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)    = +0.645 V = +1.416 V
D) Pb(s) + 2 Fe3+(aq) \to Pb2+(aq) + 2 Fe2+(s)  Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = -0.126 V Fe<sup>3+</sup>(aq) + e<sup>-</sup>  \to  Fe<sup>2+</sup>(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = +0.771 V A)  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)  \to Pb(s) + 2 Fe<sup>3+</sup>(aq)    = +0.897 V B)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)  \to  Pb(s) + Fe<sup>3+</sup>(aq)    = +0.645 V C)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +1.416 V D)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +0.897 V E)  Pb(s) + Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)    = +0.645 V = +0.897 V
E) Pb(s) + Fe3+(aq) \to Pb2+(aq) + Fe2+(s)  Given the following two half-reactions,write the overall reaction in the direction in which it is spontaneous and calculate the standard cell potential. Pb<sup>2+</sup>(aq) + 2 e<sup>-</sup>  \to  Pb(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = -0.126 V Fe<sup>3+</sup>(aq) + e<sup>-</sup>  \to  Fe<sup>2+</sup>(s)  ~~~~~~~~~~~~~~~~ E<sup> \circ </sup> = +0.771 V A)  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)  \to Pb(s) + 2 Fe<sup>3+</sup>(aq)    = +0.897 V B)  Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)  \to  Pb(s) + Fe<sup>3+</sup>(aq)    = +0.645 V C)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +1.416 V D)  Pb(s) + 2 Fe<sup>3+</sup>(aq)  \to  Pb<sup>2+</sup>(aq) + 2 Fe<sup>2+</sup>(s)    = +0.897 V E)  Pb(s) + Fe<sup>3+</sup>(aq)  \to Pb<sup>2+</sup>(aq) + Fe<sup>2+</sup>(s)    = +0.645 V = +0.645 V

F) A) and B)
G) C) and D)

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The use of electrical energy to produce chemical change is known as ________.An example of this process is the reduction of NaCl( The use of electrical energy to produce chemical change is known as ________.An example of this process is the reduction of NaCl(    )to produce Na(s). )to produce Na(s).

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electrolysis

What is the correct cell notation for a cell in which the hydrogen electrode is the anode and the cathode half-reaction is Pb4+(aq) + 2e- Pb2+(aq) .


A) Pt(s) | H2(g) | H+(aq) || Pb4+(aq) ,Pb2+(aq) | Pt(s)
B) Pt(s) | H2(g) | H+(aq) || Pb4+(aq) ,Pb2+(aq)
C) Pb2+(aq) ,Pb4+(aq) || H+(aq) | H2(g) | Pt(s)
D) Pt(s) | Pb2+(aq) ,Pb4+(aq) || H+(aq) | H2(g) | Pt(s)
E) H2(g) | H+(aq) || Pb2+(aq) ,Pb4+(aq)

F) A) and E)
G) B) and D)

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What is the correct cell notation for a voltaic cell based on the reaction below? Cu2+(aq) + Fe(s) \to Cu(s) + Fe2+(aq)


A) Cu(s) | Cu2+(aq) || Fe2+(aq) | Fe(s)
B) Fe(s) || Fe2+(aq) ,Cu2+(aq) | Cu(s)
C) Cu(s) || Cu2+(aq) ,Fe2+(aq) || Fe(s)
D) Cu(s) | Fe2+(aq) || Cu2+(aq) | Fe(s)
E) Fe(s) | Fe2+(aq) || Cu2+(aq) | Cu(s)

F) C) and D)
G) A) and E)

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E

Consider the following half-reactions: Cl2(g) + 2 e- \to 2 Cl-(aq)         ~~~~~~~~        ~~~~~~~~ E \circ = +1.36 V Ag+(aq) + e- \to Ag(s)        ~~~ ~~~~       ~~~~ ~~~      ~~ ~~~~ E \circ = +0.80 V Cu2+(aq) + 2 e- \to Cu(s)         ~~~~~~~~        ~~~~~~~~ E \circ = +0.34 V Sn2+(aq) + 2 e- \to Sn(s)       ~~~~~ ~    ~~~ ~        ~~~~~~~~ E \circ = -0.14 V Al3+(aq) + 3 e- \to Al(s)         ~~~~~~~~       ~~~ ~~~~    ~~~ E \circ = -1.66 V Which of the above elements or ions will reduce Cu2+(aq) ?


A) Ag(s) and Sn2+(aq)
B) Cl-(aq) and Ag(s)
C) Cl2(g) and Ag+(aq)
D) Sn(s) and Al(s)
E) Sn2+(aq) and Al3+(aq)

F) B) and D)
G) B) and E)

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Which of the following are standard conditions for an electrochemical cell? 1) Solutes in aqueous solution has a concentration of 1 M. 2) Gaseous reactants or products have a pressure of 1 bar. 3) Solids are present in quantities of 1 mole.


A) 1 only
B) 2 only
C) 3 only
D) 1 and 2
E) 1,2,and 3

F) None of the above
G) A) and E)

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The unit for electromotive force,emf,is the Volt.A Volt is equal to


A) one joule per second.
B) one coulomb per joule.
C) one joule per coulomb.
D) one coulomb per second.
E) one second per joule.

F) B) and C)
G) A) and B)

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The following reaction occurs spontaneously. 2 Fe(s) + 3 Cl2(aq) \to 2 Fe3+(aq) + 6 Cl-(aq) Write the balanced oxidation half-reaction.


A) Fe(s) \to Fe3+(aq) + 3 e-
B) Fe(s) + 3 e- \to Fe3+(aq)
C) Fe(s) + 3/2 Cl2(aq) \to FeCl3(aq)
D) Cl2(aq) \to 2 Cl-(aq) + 2 e-
E) Cl2(aq) + 2 e- \to 2 Cl-(aq)

F) A) and B)
G) A) and C)

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