Question 1

A well-designed voltage-divider bias circuit is one in which the voltage divider appears

Accepted Answer

A)   stiff to the input resistance of the base.
B)   soft to the input resistance of the base.
C)   stiff to the output resistance of the collector.
D)   stiff to the input resistance of the emitter.E) A) and B)
F) B) and D)

Question 2

In Figure 7-5,if the fuse blows open

Accepted Answer

A)   the transistor is biased on and the green LED illuminates.
B)   the transistor is biased off and the green LED illuminates.
C)   the transistor is biased on and the red LED illuminates.
D)   the transistor is biased off and the red LED illuminates.E) All of the above
F) A) and B)

Question 3

A firm voltage divider means that the collector current will be approximately 10 percent lower than the stiff value.

Accepted Answer

A) True 
 B)False

Question 4

With the values shown at the operating point labeled Q,the voltage across RC would be 10 V.

Accepted Answer

A) True 
 B)False

Question 5

The emitter current in the circuit shown in Figure 7-12 can be calculated by dividing +10 V by 1 kW.

Accepted Answer

A) True 
 B)False

Question 6

The schematic diagram of a pnp transistor shows

Accepted Answer

A)   the emitter as an arrow pointing in.
B)   the emitter as an arrow pointing out.
C)   the collector as an arrow pointing in.
D)   the collector as an arrow pointing out.E) A) and D)
F) C) and D)

Question 7

In Figure 7-18,the negative supply

Accepted Answer

A)   forward-biases the emitter diode.
B)   forward-biases the collector diode.
C)   reverse-biases the emitter diode.
D)   reverse-biases the collector diode.E) A) and D)
F) B) and D)

Question 8

In the circuit shown in Figure 7-29 (a) ,the base voltage can be calculated by 1 and R2 and the supply voltage. B)  using the voltage divider rule using RC and RE and the supply voltage. C)  multiplying collector current by the collector resistor. D)  multiplying emitter current by the emitter resistor." class="answers-bank-image d-inline" rel="preload" >

Accepted Answer

A)   using the voltage divider rule using R1 and R2 and the supply voltage.
B)   using the voltage divider rule using RC and RE and the supply voltage.
C)   multiplying collector current by the collector resistor.
D)   multiplying emitter current by the emitter resistor.E) C) and D)
F) A) and B)

Question 9

In order to calculate the base voltage for the circuit shown in Figure 7-29 (b)  2 by the sum of R1 and R2 and then multiply by 10 V. B)  divide R1 by the sum of R1 and R2 and then multiply by 10 V. C)  divide RC by the sum of RE and RC and then multiply by 10 V. D)  divide RE by the sum of RE and RC and then multiply by 10 V." class="answers-bank-image d-inline" rel="preload" >

Accepted Answer

A)   divide R2 by the sum of R1 and R2 and then multiply by 10 V.
B)   divide R1 by the sum of R1 and R2 and then multiply by 10 V.
C)   divide RC by the sum of RE and RC and then multiply by 10 V.
D)   divide RE by the sum of RE and RC and then multiply by 10 V.E) A) and C)
F) A) and B)

Question 10

Voltage-divider bias produces a fixed value of emitter current that results in a stable operating point that is

Accepted Answer

A)   always located at cutoff.
B)   always located at saturation.
C)   dependent on the current gain.
D)   independent of the current gain.E) C) and D)
F) A) and C)

Exam 7: BJT Biasing

In the circuit shown in Figure 7-29 (a) ,the base voltage can be calculated by

Correct Answer
verified

In Figure 7-5,if the fuse blows open

Correct Answer
verified

The schematic diagram of a pnp transistor shows

Correct Answer
verified

With the values shown at the operating point labeled Q,the voltage across R_C would be 10 V.

Correct Answer
verified

A well-designed voltage-divider bias circuit is one in which the voltage divider appears

Correct Answer
verified

In order to calculate the base voltage for the circuit shown in Figure 7-29 (b)

Correct Answer
verified

Voltage-divider bias produces a fixed value of emitter current that results in a stable operating point that is

Correct Answer
verified

A firm voltage divider means that the collector current will be approximately 10 percent lower than the stiff value.

Correct Answer
verified

In Figure 7-18,the negative supply

Correct Answer
verified

The emitter current in the circuit shown in Figure 7-12 can be calculated by dividing +10 V by 1 kW.

Correct Answer
verified

Exam 7: BJT Biasing

In the circuit shown in Figure 7-29 (a) ,the base voltage can be calculated by

Correct AnswerverifiedShow Answer

In Figure 7-5,if the fuse blows open

Correct AnswerverifiedShow Answer

The schematic diagram of a pnp transistor shows

Correct AnswerverifiedShow Answer

With the values shown at the operating point labeled Q,the voltage across RC would be 10 V.

Correct AnswerverifiedShow Answer

A well-designed voltage-divider bias circuit is one in which the voltage divider appears

Correct AnswerverifiedShow Answer

In order to calculate the base voltage for the circuit shown in Figure 7-29 (b)

Correct AnswerverifiedShow Answer

Voltage-divider bias produces a fixed value of emitter current that results in a stable operating point that is

Correct AnswerverifiedShow Answer

A firm voltage divider means that the collector current will be approximately 10 percent lower than the stiff value.

Correct AnswerverifiedShow Answer

In Figure 7-18,the negative supply

Correct AnswerverifiedShow Answer

The emitter current in the circuit shown in Figure 7-12 can be calculated by dividing +10 V by 1 kW.

Correct AnswerverifiedShow Answer

Correct Answer
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Correct Answer
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Correct Answer
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With the values shown at the operating point labeled Q,the voltage across R_C would be 10 V.

Correct Answer
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Correct Answer
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Correct Answer
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Correct Answer
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Correct Answer
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Correct Answer
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